a sum of Rs 8.85 is made up of 124 coins, some of which are 10 paise coins and rest are 5 paise coins.how many are there of each?
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1Rs = 100paise
8.85Rs = 885Rs
let no.of 10paise coins = x
no.of 5paise coins = y
x + y = 124........eq1
10x + 5y = 885..........eq2
eq1*5 5x + 5y = 620
eq2 10x + 5y = 885
- - -
____________________
-5x = - 265
x = - 265/-5
= 53
from eq 1.....
53 + y = 124
y = 124 - 53
= 71
Therefore 53 number of 10paise coins and 71 number of 5 paise coins made 885 paise (or) 8.85.
Hope this helps u ..
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8.85Rs = 885Rs
let no.of 10paise coins = x
no.of 5paise coins = y
x + y = 124........eq1
10x + 5y = 885..........eq2
eq1*5 5x + 5y = 620
eq2 10x + 5y = 885
- - -
____________________
-5x = - 265
x = - 265/-5
= 53
from eq 1.....
53 + y = 124
y = 124 - 53
= 71
Therefore 53 number of 10paise coins and 71 number of 5 paise coins made 885 paise (or) 8.85.
Hope this helps u ..
please mark me as the brainliest.....
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