A sum of Rs. 800 is in the form of denominations of Rs.10& Rs.20 . if the total number of notes is 50 , find the number of notesof each type
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suppose that the notes of 10 are x so the notes of 20 will be 50-x .
Given
10x + 20(50-x) =800
10x + 1000 - 20x = 800
1000 - 10x = 800
10x = 1000 - 800
10x = 200
x = 20
so the notes of 10 will be 20 and the notes of 20 will be 50 - 20 = 30.
Given
10x + 20(50-x) =800
10x + 1000 - 20x = 800
1000 - 10x = 800
10x = 1000 - 800
10x = 200
x = 20
so the notes of 10 will be 20 and the notes of 20 will be 50 - 20 = 30.
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Heya user !!!
Here's the answer you are looking for
⏩ Let there are x ₹10 notes.
Since total number of notes = 50
number of ₹20 notes = (50 - x)
⏩ All the notes add up to ₹800
That means, ₹10(x) + ₹20(50 - x) = ₹800
10x + 1000 - 20x = 800
-20x + 10x = 800 - 1000
-10x = -200
x = 20
⏩ Therefore, there are twenty ₹10 notes and thirty ₹20 notes.
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
⏩ Let there are x ₹10 notes.
Since total number of notes = 50
number of ₹20 notes = (50 - x)
⏩ All the notes add up to ₹800
That means, ₹10(x) + ₹20(50 - x) = ₹800
10x + 1000 - 20x = 800
-20x + 10x = 800 - 1000
-10x = -200
x = 20
⏩ Therefore, there are twenty ₹10 notes and thirty ₹20 notes.
★★ HOPE THAT HELPS ☺️ ★★
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