Math, asked by nishkarsh10, 1 year ago

A sum of Rs. 800 is in the form of denominations of Rs 10 & Rs 20.If the total no. of notes is 50, find the number of notes of each type. (IN ONE VARIABLE)

Answers

Answered by neha1a2b3c4d
11

Let the no of 10rupee note be x Then the no of 20rupee note =50-x According to question 10*x+ 20(50-x) =800 -10x =800-1000 X= 20 No of 10rupee notes = 20 No of 30 rupee note = 50-x                                      50-20 =30 Hope it may help you

Answered by Misty29
9

Hey there Total amount = ₹800 Let no: of ₹10 notes be x. Total no: of notes = 50 No: of ₹20 notes = 50-x Total money denomination by ₹10 = ₹10x Total money denomination by ₹20 = ₹20(50-x) ₹1000-20x Now, according to question:- 10x+1000-20x = 800 10x-20x = 800-1000 -10x = - 200 x = - 200/-10 x = 20 Hence, No: of ₹10 notes = 20              No: of ₹20 notes = 50-20=30 Hope it helps you...  

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