Question

A sum of Rs 800is on the form
of denomination of Rs 10 and Rs 20
if the total number of notes, is

50, find the no. of notes of each tyhe-​

Answer 1

Solution :

Let the number of 10 rupees note be x and 20 rupees not be ( 50 - x)

Total sum = 800

Now,

10 rupee notes = 10x and

20 rupee notes = 20(50 - x)

According to the question :

$\longrightarrow \sf \: 10x + 20(50 - x) = 800$

$\longrightarrow \sf \: 10x + 1000 - 20x = 800$

$\longrightarrow \sf \: 10x - 20x + 1000= 800$

$\longrightarrow \sf \: - 10x = 800 - 1000$

$\longrightarrow \sf \: - 10x = - 200$

$\longrightarrow \sf \: x = \dfrac{200}{10}$

$\longrightarrow \sf \: x =20$

$\therefore$ Number of 10 rupee notes = 20 and number of 20 rupee notes = (50 - 20) = 30

Answer 2

Answer:

Step-by-step explanation:

so total notes =50

let no of  Rs 10 notes be y

then no. of Rs 20 notes = 50-y

so (10 x y )+[20 x (50-y)]=800

10y + 1000-20y=800

-10y=800-1000

-10y = -200

y= -200/ -10

y=20

so there are 20 ten rupee notes and 30 twenty rupee notes