Question

a sum of rupees 10,000 is borrowed at the rate of interest 15% p.a in for 2 years. find simple interest and the amount to be paid at the end of 2 years

Answer 1

$\huge \underline \mathbb {SOLUTION:-}$

Answer:

• The amount to be paid at the end of 2 years = ₹ 13,000

Given:

• P = 10, 000
• R = 15%
• T = 2 Years

Need To Find:

• Simple Interest = ?
• Amount = ?

Explanation:

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Case 1:

• Find the simple interest = ?

Formula used here:

• SI = P × R × T/100

Putting the values according to the given formula:

➠ 10,000 × 15 × 12/100

➠ 100 × 15 × 12

➠ ₹ 3,000

• Hence, the simple interest = ₹ 3,000

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Case 2:

• Find the amount = ?

Formula used here:

• Amount = P + SI

Putting the values according to the given formula:

➠ Amount = ₹10,000 + ₹3,000

➠ Amount = ₹13,000

• Hence, the amount to be paid at the end of 2 years = ₹13,000

Additional Information:

Here:

• P is used for Principal
• R is used for Rate of Interest
• T is used for Time
• SI is used for Simple Interest

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Answer 2

ANSWER :-

• Simple Interest = 3000

• Amount = 13000

GiVeN:-

• Principal (P) = 10,000

• Rate (R) = 15%

• Time (T) = 2years

To FiNd :-

• Simple Interest (S. I.)

• Amount (A)

SoLuTiOn:-

We know that ,

Simple Interest (SI) =

$\implies \: \frac{PRT}{100} \\ \\ \implies \: \frac{10000 \times 15 \times 2}{100} \\ \\ \implies \: \frac{300000}{100} \\ \\ \implies \: 3000$

Hence,

Simple Interest = 3000

Now,

We know that,

Amount (A) = Principal (P) + Interest (I)

Amount (A) = 10000 + 3000 = 13000