a sum of rupees 1000 is invested at 8% simple interest per year calculate the interest at the end of each year the interest for first and second and third year from an ap if so find the total interest to be paid for 30 years making the use of this fact
Answers
Given,
principal=1000
rate of interest=8%
number of years=1 year
SI=Pnr/100=1000x1x8/100=rs.80
when n=2 years,SI=1000x2x8/100=rs.160
when n=3years,SI=1000x3x8/100=rs.240
the sequence is
80,160,240,..........
this is in AP as a,first term=80,d,common difference=80
interest at the end of 30 years,t30=a+(n-1)d
=80+(30-1)80
=80+29(80)
=80+2320
=2400
so 24 is the answer
ʜᴇʏᴀ ᴍᴀᴛᴇ!!
ʜᴇʀᴇ ɪs ᴜʀ ᴀɴsᴡᴇʀ ⏬ ⏬
sɪᴍᴘʟᴇ ɪɴᴛᴇʀᴇsᴛ = ᴘ × ʀ × ᴛ ÷ 100
sᴏ s.ɪ ɪɴ ғɪʀsᴛ ʏʀ. ⇒ ᴘ x ʀ x ᴛ / 100
⇒ 1000 x 1 x 8 ÷ 100
⇒ 80
ɪɴ sᴇᴄᴏɴᴅ ʏʀ. ⇒ 1000 x 2 x 8 ÷ 100
⇒ 160
sɪᴍɪʟᴀʀʟʏ ɪɴ ᴛʜɪʀᴅ ʏʀ. ⇒ 240
sᴏ , ᴡᴇ ɢᴇᴛ ᴛʜᴇ ᴀ.ᴘ. ʟɪᴋᴇ ᴛʜɪs ɪ.ᴇ. 80, 160, 240
ᴛʜᴇʀᴇғᴏʀ ᴀ= 80 , ᴅ= 80.
ᴡᴇ ʜᴀᴠᴇ ᴛᴏ ғɪɴᴅ ᴏᴜᴛ ᴛʜᴇ ɪɴᴛᴇʀᴇsᴛ ᴀᴛ ᴛʜᴇ ᴇɴᴅ ᴏғ 30 ʏʀ.
⇒ ᴀ = ᴀ + ( ɴ-1 ) ᴅ
⇒ 80 + ( 30 - 1 ) 80
⇒ 80 + 29 × 80
⇒ 2400
ᴛʜᴇʀᴇ ғᴏʀᴇ , ᴛʜᴇ ɪɴᴛᴇʀᴇsᴛ ᴀᴛ ᴛʜᴇ ᴇɴᴅ ᴏғ 30 ʏʀs ɪs 2400