A sum of rupees 1000 is invested at 8% simple interest per annum. calculate the interest at the end of 2,3...years
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Answered by
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For 2 years
Simple interest= PNR/100
= 1000 × 8 ×2 /100
=160 rs
For 3 years
Simple Interest= PNR /100
=1000 × 8 ×3 /100
= 240
Simple interest= PNR/100
= 1000 × 8 ×2 /100
=160 rs
For 3 years
Simple Interest= PNR /100
=1000 × 8 ×3 /100
= 240
Answered by
0
Hi ,
Principal ( p ) = Rs1000
Rate of interest ( r ) = 8 %
Time ( t ) = 1 year
Simple interest ( s.I ) = ptr/100
S.I = ( 1000 × 1 × 8 ) /100
= Rs 80----( 1 )
Therefore ,
Interest for 2 years = 2 × ( 1 )
= 2 × 80 = Rs160
Interest for 3 years = 3 × ( 1 )
= 3 × 80 = Rs 240
Interest for n years = n × 80
I hope this helps you.
:)
Principal ( p ) = Rs1000
Rate of interest ( r ) = 8 %
Time ( t ) = 1 year
Simple interest ( s.I ) = ptr/100
S.I = ( 1000 × 1 × 8 ) /100
= Rs 80----( 1 )
Therefore ,
Interest for 2 years = 2 × ( 1 )
= 2 × 80 = Rs160
Interest for 3 years = 3 × ( 1 )
= 3 × 80 = Rs 240
Interest for n years = n × 80
I hope this helps you.
:)
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