Question

A sum of rupees 2800 is to be used to award 4prizes. If each prize after the first is rupees 200 less than the preceding prize, find the value of each of these prizes. (arithmetic progression) ​

Answer 1

Answer:

oyoyadhdykahscksjhDjxdngcdh

Answer 2

Answer:

• 1st prize(a)=Rs.1000
• 2nd prize(a2)=Rs.800
• 3rd prize(a3)=Rs.600
• 4th prize(a4)=Rs.400

__________________________

Step-by-step explanation:

given:

d= -200

Sn= 2800

To find:

a=?

__________________________________

$\: \: \: \: \: \: \: \: \: \: \: \: sn = \frac{n}{2} (2a + (n - 1)d) \\ = > 2800 = \frac{4}{2} (2a + (4 - 1) - 200) \\ = > 2800 = \frac{4}{2} (2a + 3 \times ( - 200)) \\ = > 2(2800) = 4(2a + ( - 600)) \\ = > 5600 = 8a - 2400 \\ = > 5600 + 2400 = 8a \\ = > 8000 = 8a \\ = > a = \frac{8000}{8} \\ = > a = 1000$

an=a+(n-1)d

____________________

a2=1000+(2-1)-200=1000+1×(-200)=1000-200

a2=800

_____________________

a3=1000+(3-1)-200=1000+2(-200)=1000-400

a3=600

_____________________

a4=1000+(4-1)-200=1000+3(-200)=1000-600

a4=400

________________________________

**********hope it is clear to uh*****************

------------------------------------------