a sum of rupees 3000 is to be given in the form of 63 prizes, If the prize money is either Rs.100 or Rs. 25 find the number of prizes of each type
Answers
Answered by
120
Hi friend
Total sum is 3000 rupees
Total no of prizes is 63
then x+y=63. (1)
100x+25y=3000. (2)
By simplifying 2 nd equation we get
4x+y=120. (3)
we have to subtract equation 1 from equation 3
4x+y-x-y=120-63
3x=57
x=19
put x=19 in equation 1
19+y=63
y=63-19=44
no of prizes of rs 100 =19
no of prizes of rs 25=44
HOPE IT HELPS YOU...
Total sum is 3000 rupees
Total no of prizes is 63
then x+y=63. (1)
100x+25y=3000. (2)
By simplifying 2 nd equation we get
4x+y=120. (3)
we have to subtract equation 1 from equation 3
4x+y-x-y=120-63
3x=57
x=19
put x=19 in equation 1
19+y=63
y=63-19=44
no of prizes of rs 100 =19
no of prizes of rs 25=44
HOPE IT HELPS YOU...
Answered by
18
Answer:
19 or 44
Step-by-step explanation:
Let the number of prizes of money 100 be x, and the number of prizes of cost 25 be y ;
x+y = 63
y = 63-x -------(1)
100x+25y = 3000
4x+y = 120
y = 120-4x ------(2)
63-x = 120-4x
4x-x = 120-63
3x = 57
x = 19
y = 63-x = 63-19
y = 44
Hence the number of prizes of cost 100 each are 19 while other type of prizes are 44
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