Question

a sum of Rupees 390 was divided among 45 boys and girls. Each boy get Rs. 5, where as a girl get Rupees 10. Find the number boys and girls.​

Answer 1

Given :- a sum of Rupees 390 was divided among 45 boys and girls. Each boy get Rs. 5, where as a girl get Rupees 10. Find the number boys and girls.

Answer :-

Let us assume that,

• Total number of boys = x .
• Total number of girls = y .

so,

→ x + y = 45 -------- Eqn.(1)

since, Each boy get Rs. 5, where as a girl get Rupees 10 and total amount is Rs.390 .

→ 5x + 10y = 390

→ 5(x + 2y) = 390

→ x + 2y = 78 ------- Eqn.(2)

subtracting Eqn.(1) from Eqn.(2)

→ (x + 2y) - (x + y) = 78 - 45

→ x - x + 2y - y = 33

→ y = 33 .

putting value of y in Eqn.(1)

→ x + 33 = 45

→ x = 45 - 33

→ x = 12 .

therefore, total number of b oys are 12 and total number of gi rls are 33.

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Answer 2

Given:

A sum of Rupees 390 was divided among 45 boys and girls. Each boy gets Rs. 5, whereas the girl gets rupees 10

To Find:

The number of Boys and Girls.

Solution:

Let the number of boys = B

Let the number of girls = G

It is given that there are total children = 45

=> B + G = 45 -------------(Equation 1)

It is given that a sum of Rs390 is divided. Each boy gets Rs.5, whereas the girl gets Rs.10.

=> 5B + 10G = 390

Take out 5 as common.

=> 5(B + 2G) = 390

=> B + 2G = 390/5

=> B + 2G = 78 ------------(Equation 2)

Finding the Number of Girls:

Subtract (Equation-1) from (Equation 2)

=> (B + 2G = 78) - (B + G = 45)

=> B + 2G - B - G = 78 - 45

=> G = 33

So, Girls = 33.

Finding the Number of Boys:

Substitute G=33 in (Equation 1)

=> B + G = 45

=> B + 33 = 45

=> B = 45 - 33

=> B = 12

So, Boys = 12

Hence, The number of Boys = 12, The number of Girls = 33