Math, asked by sainadhvm, 1 year ago

A sum of rupees 731 /- is divided among A,B and C such that A receive 25% more than B and B receives 25% less than C .What is "C"share in the amount?

Answers

Answered by hukam0685
12

Answer:

Share of C is 272 Rs.

Step-by-step explanation:

To solve such questions, assume that C receive x rupees.As A received 25% more than B

So B received : x-25% of x

 = x  -  \frac{25x}{100}  \\  \\  =  \frac{75x}{100}  \\  \\

A received 25% more than B: 75x/100+25% of 75x/100

 =  \frac{75x}{100}   +   \frac{25 \times 75x}{10000}  \\  \\  =  \frac{9375x}{10000}  \\  \\

So,

x +  \frac{75x}{100}  +  \frac{9375x}{10000}  = 731 \\  \\  \frac{10000x + 7500x + 9375x}{10000}  = 731 \\  \\ 26875x = 7310000 \\  \\ x =  \frac{7310000}{26875}  \\  \\ x =  \frac{731}{3}  \\  \\ x = 272 \\  \\

Share of C is 272 Rs.

Hope it helps you.

Answered by Haezel
13

Answer:

C's share is Rs.272.

Step-by-step explanation:

To find the share amount of C, first we have to calculate the share of A and B with the given data.

The total amount = Rs 731.

A received 25% more than B.

Hence, A received  =\frac{100+25}{100} \times B

\Rightarrow \frac{A}{B}=\frac{125}{100}=\frac{5}{4}

And, B receives 25% less than C.

Hence, B received =  \frac{100-25}{100} \times C

\Rightarrow \frac{B}{c}=\frac{75}{100}=\frac{3}{4}

Hence, A:B = 5:4  and  B:C = 3:4

A:B = 15:12          B:C = 12:16

So, A:B:C = 15:12:16.

Thus, C’s share \begin{array}{l}{=\frac{16}{15+12+16} \times R s 731=\frac{16}{43} \times R s 731} \\ {=16 \times \mathrm{Rs} 17=\mathrm\bold{{Rs} 272}}\end{array}  

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