Math, asked by 9610697164, 1 year ago

A sum of rupees 76 is devided among A,B and C in such a way that A gets rupees 7 more than what B gets and B rupees 6 more than what C gets . The ratio of their share is

Answers

Answered by shrutispawar
0

Answer:

Step-by-step explanation:

Let C gets x rupees

B gets x + 6 rupees

A gets x + 6 + 7 rupees

= A + B + C => (3x + 19)

3x + 19 = 76

3x = 76 - 19 => 57

x = 19

∴ A gets = 19 + 13 = Rs. 32

B gets = 19 + 6 = Rs. 25

C gets = Rs. 19

∴ A : B : C

32 : 25 : 19

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