Question

a sum of rupees 9600 is invited for 3 year at 10% p.a. compound interest (a) what is the amount at the end of the first year? ( b) what is the amount at the end of second year? ( c) find the compound interest earned in the first 2 years (d) find the compound interest earned and end of 3 year?​

Answer 1

Step-by-step explanation:

A=P(1+r/100)*n

according to question (a)

A=9600(1+10/100)

=9600×11/10

= 10560

according to question (b)

A=P(1+r/100)*n

= 10560(1