A sum of the square of three consecutive even integers is 200
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Let there consecutive even integers be X, x+2,x+4
X^2+(x+2)^2+(x+4)^2=200
X^2+x^2+4x+4+x^2+8x+16=200
3x^2+12x-180=0
X^2+4x+60=0
X=-10 or 6
So numbers are 6,8,10 or -10,-8,-6
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