Question

A sum of two digit whose sum is 9 if 27 is subtracted from the number it's digits are revered. Find the number

Answer 1

Answer:

let one of the digit=x

other digit =(9-x)

digit so formed = 10x+9-x

=9x+9

now the reversed digit=10×(9-x) + x

=90-10x+x

=90-9x

but given that if we subtract 27 from the original number we will get the reversed one.

therefore, 9x+9-27=90-9x

=9x-18=90-9x

=9x+9x=90+18

=18x=108

=x=108/18

=x=6

that is, the numbers =x=6

and 9-x=9-6=3

therefore number soformed =63