A sum of two number is 72. If one of the number is 6 more than other, find the number s
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Let the number be 'x'
one of the number is 6 more than other=x+6
x+x+6=72
2x+6=72
2x=72-6
2x=66
x=66÷2
x=33
x+6 ; 33+6=39
Let the number be 'x'
one of the number is 6 more than other=x+6
x+x+6=72
2x+6=72
2x=72-6
2x=66
x=66÷2
x=33
x+6 ; 33+6=39
Answered by
0
Answer:
Step-by-step explanation:
x = (72 - x) + 6
x = 72-x
x+x =78
2x = 78
x = 78/2
= 39
Hence the first no. is 39
and other is 72-39=33
two numbers are 39 & 33
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