Math, asked by phanitejamanikonda, 9 months ago

a sum required to earn a monthly interest of 1200 at 18% per annum SI is​

Answers

Answered by danishking61
5

Answer:

let the sum = Rs. x

time = 1/12 years (as 1 month = 1/12)

SI = 1200 , R = 18 percentage

SI = PRT/100

1200 = x * 18 * 1 the whole divided by 100 * 12

x = 1200 * 100 * 12 the whole divided by 18

So, x = 40000 * 2

therfore , x = 80000

so the sum us 80000

Step-by-step explanation:

check SI = PRT/100

SI = 80000 * 18 * 1 the whole divided by 12 * 100

So SI = 1200

HOPE U UNDERSTOOD

Answered by AllenGPhilip
1

Answer:

Step-by-step explanation:

Refer my notes

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