Math, asked by Gunpreet4039, 9 months ago

A sum was invested at simple interest at a certain rate 4 year had it been had it been put at 6% higher rate it eould has fetched 3600more what was sum invested

Answers

Answered by tushar791
0

Answer:

3600×4×6÷100= 864

A=3600+864=4464

Step-by-step explanation:

SI=P×T×R% (P=3600,T=4

YEAR, RATE= 6%)

SI=3600×4×6÷100=864

AMOUNT = P+SI

AMOUNT =3600+864=4464

Answered by Agastya0606
0

Answer:

Rs 15000

Step-by-step explanation:

A sum of money was invested at Simple interest at certain rate for 4 years.

If the rate was 6% higher than the initial , it could have fetched Rs 3600 more.

So, according to the problem,we know that

S.I= (p * r * t)/100

p=principal money, r= rate of interest, t= time

So now considering 6% higher rate would have fetched rs 3600 more, now the rate becomes 6+r.

Hence according to the given problem , we can deduce:

p*(r+6)*4              p*r*4

_________  -   _______  = 3600

 100                     100

4pr+24p         4pr

_______   -   _____    =3600

 100                100

     24p/100 =3600

     24p= 3600 * 100

       p= (3600 *100)/24

       p= 15000

Therefore the sum of money invested was Rs 15000.

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