Question

A sumarine moved from water surface of - 20 m per min

Answer 1

$\huge{\underline{\mathbb{\red{SOLUTION:-}}}}$

$\tt\large\green{Given:-}$

Distance covered by submarine in 1 min = 20m

So,

$speed = \frac{distance}{time}$

So,

Speed of Submarine = 20meter ÷ 60sec

i.e.

$\frac{20 \: meter}{60sec} \\ = \frac{1}{3} m \: per \: sec \\ = 0.33...m \: per \: sec$