Question

A sumbarine is at 350 m below sea level. It ascends for 10seconds and then stops. It's final position is 100m below see level. Find the speed of the submarine.
I hope that anyone will help me​

Answer 1

Answer:

Given –

• Initial position of submarine = 350 metres below sea level.
• Final position of submarine = 100 metres below sea level.
• Time taken to ascend = 10 seconds.

To Find –

• The speed of the submarine.

Solution –

The Total distance travelled by the submarine = 2l350 - 100 = 250 metres.

Total time taken to travel 250 metres, given is, 10 seconds.

Formula used : Speed = Distance/Time.

➸ Speed = 250/10

➸ Speed = 25 metres/second

➸ Speed = 25 m/s

Hence, the speed of the submarine is 25 metres per second.

Answer 2

GIVEN:

• Initial position of submarine is 350 m below seas level
• Final position of submarine = Initial position– 100 m below sea level
• Time taken for ascending is 10 seconds

TO FIND:

• What is speed of submarine ?

FORMULA USED:

$\bf{ Speed = \dfrac{Distance}{Time}}$

SOLUTION:

➭ Initial position of submarine before ascending= 350 m

➭ Final position of submarine after ascending = 350–100 = 250 m

➭ We have given that the time taken by the submarine is 10 Seconds

According to question:-

On Putting the values in the formula, we get

$\bf{\mapsto Speed = \dfrac{Distance}{Time}}$

$\rm{\mapsto Speed = \cancel\dfrac{250}{10}}$

$\bf{\mapsto Speed = 25 m/s }$

 ❝ Hence, the speed of submarine is 25 m/s. ❞

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✬ Extra Information ✬

➜ Distance = Speed $\times$ Time

➜ Time = Distance/Speed

➜ Velocity = Displacement/Time