Math, asked by sss670, 1 year ago

a sumof rs 800is lent for one year at the rate of 18%per annum the interest

Attachments:

Answers

Answered by Mercidez
1
 \: \: \: \: \: \: \: \: \: \: Your \: \: \: \: \: \: Answer \\ - - - - - - - - - - - - -

Given, \\

P = ₹ 800

R = 18\% \: p.a. \\ \\ T = 1 \: \: year \\

Now, \\ Interest \: \: = \frac{P \times R \times T}{100} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{800 \times 18 \times 1}{100} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 144

Hence, Required Interest is ₹ 144
Answered by nehu215
2

Answer:

Solution :

Let the number of 10 rupees note be x and 20 rupees not be ( 50 - x)

Total sum = 800

Now,

10 rupee notes = 10x and

20 rupee notes = 20(50 - x)

According to the question :

\longrightarrow \sf \: 10x + 20(50 - x) = 800⟶10x+20(50−x)=800</p><p></p><p>[tex]\longrightarrow \sf \: 10x + 1000 - 20x = 800⟶10x+1000−20x=800

\longrightarrow \sf \: 10x - 20x + 1000= 800⟶10x−20x+1000=800

\longrightarrow \sf \: - 10x = 800 - 1000⟶−10x=800−1000

\longrightarrow \sf \: - 10x = - 200⟶−10x=−200

\longrightarrow \sf \: x = \dfrac{200}{10}⟶x=

10

200

\longrightarrow \sf \: x =20⟶x=20

\therefore∴ Number of 10 rupee notes = 20 and number of 20 rupee notes = (50 - 20) = 30

Step-by-step explanation:

hope it help

Similar questions