A supply of 12V DC is applied across a circuit which consists of three resistors connected in parallel R=1.25 ohms, R2=5.6 ohms, R3=2.1 ohms, and a fourth resistor of 7.8 ohms connected in series with the parallel group. Determine the current, voltage, and power across each resistor
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Explanation:
R1= 1.25 ohm
R2= 5.6 ohm
R3= 2.1 ohm
R4= 7.8 ohm
1/r= (1/R1+1/R2+1/R3)
= (1/1.25+1/5.6+1/2.1)
= 0.8+ 0.17+ 0.47
= 1.44
r= 1/1.44= 0.69 ohm
total resistance R = 0.69+ 7.8= 8.49 ohm
voltage V= 12 volt
current I = V/R
= 12/8.49
= 1.41 amp
power P= I^2R
= (1.41)^2* 8.49
= 16.87 watt
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