A supportive young hare and tortoise raced in opposite directions around a circular track that was 100 yards in diameter. they started at the same spot, but the hare did not move until the tortoise had a start of one eighth of the distance ( that is, the circumference of the circle). the hare held such a poor opinion of the other's racing ability that he sauntered along, nibbling the grass until he met the tortoise. at this point the hare had gone one sixth of the distance. how many times faster than he went before must the hare now run in order to win the race ?
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the hare and the tortoise are at d same point when hare have to cover 5/6 of the dist n tortoise have to covet 1/6 of the dist to complete the race...
if x is d speed of tortoise then it'll take 1/(6x) time to finish..
so, hare will have to run more then 5 times the speed of tortoise to win the race.
Ans: more than 5 times
if x is d speed of tortoise then it'll take 1/(6x) time to finish..
so, hare will have to run more then 5 times the speed of tortoise to win the race.
Ans: more than 5 times
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