Question

a) Suppose ∠AOB and ∠BOC are supplementary angles. If m∠AOB = (9x + 7)° and m∠BOC = (13x − 3)°, What are the measures of the two angles?


b) Suppose ∠ABC and ∠CDE are complementary angles. If m∠ABC = (5x + 7)° and m∠CDE = (3x + 3)°, What are the measures of the two angles?

Answer 1

Answer:

A) 79° and 101°.

Step-by-step explanation:

A). <AOB +<BOC=180°

(9x+7)° + (13x − 3)°= 180°

22x + 4 = 180°

X = 176°/22

X= 8

Now, <AOB = (9*8+ 7)

=79°

<BOC= (13*8 -3)

=101°

Answer 2

EXPLANATION

(9x+7)and(13x-3)° is supplementary angles

so

(9x+7)+(13x-3)=180

22x+7-3=180

22x+4=180

22x =180-4

22x =176

x =176/22

x = 8

now we know that x is 8

in AOB

(9x+7) is

9×x+7

=9×8+7

=72+7

=79

in BOC

(13x-3) is

13×8-3

104-3

=101

and for checking if we will add this answers

79+101

we will get 180

which is a supplementary angle

now this is complementary angle so we will take 90

(5x+7)+(3x+3)=90

8x+7+3=90

8x+10=90

8x=90-10

8x=80

x=80/8

x=10

x is 10 so

in ABC

(5x+7)

=5×10+7

=57

in CDE

(3x+3)

=3×10+3

=33

when we will add for checking we will get

57+33

=90

that is complementary angle

FINAL ANSWERS

a). (5x+7) and (13x-3) = 79 and 101 respectively

b). (5x+7) and (3x+3) = 57 and 33 respectively

Brainliest please