A surface encloses an electric dipole. What about the electric lines would come out or
not? If not, then what would be a suitable reason.
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The electric lines will come out only if the surface is Gaussian.
Explanation:
- These electric lines will start from the positive and end on the negative charge.
- But if there are other forces are present near the enclosed surface then only some of the positive charges will be able to come out.
- This is due to the interference of other charges around the surface.
- These Gaussian objects are three dimensional.
- They have a vector field.
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