A surney of 125 families in group should following
No of car owned
309 more
NO. O families
50
10
out of these families selected at random,
probability of
p. (no car)
b)
P. (1 car only)
(e) p (3 or more car)
(& p (more than I car)
2
2
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Answer:
families:5,50,60,10 out of these families selected at random, woire probability a) p ( no Car) = b) p (1 Car Only) ...
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