A survey of 500 randomly selected adult men showed that the mean time they spend per week watching sports on television is 9.75 hours with a standard deviation of 2.2 hours. Construct a 90% confidence interval for the population mean, µ.
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Given : A survey of 500 randomly selected adult men showed that the mean time they spend per week watching sports on television is 9.75 hours
with a standard deviation of 2.2 hours.
To Find : 90% interval
Solution:
Mean = 9.75
SD = 2.2
90% interval will be from 5 % to 95 %
Z score for 5 % = -1.645
Z score for 95 % = 1.645
Mean + Z score *SD = 9.75 + (1.645)2.2 = 13.369
Mean - Z score *SD = 9.75 - (1.645)2.2 = 6.131
90 % interval
6.131 - 13.369 Years
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