Math, asked by sahumanis66pdpb3e, 11 months ago

A survey of 500 television viewers produced the following information,285 watch football,195 watch hockey,115 watch basketball,45 watch football and basketball,70 watch football and hockey,50 watch hockey and basketball and 50 do not watch any of the three games.
1)How many watch all the three games?
2)How many watch exactly one of the three games?
reply fast! tmr is my maths test.

Answers

Answered by sindhu18
200
Let F denote people watch football.

H denotes people watch hockey.

B denotes people watch basketball.

Now,

|F|=285

|H|=195

|B|=115

|FՈH| =70

|FՈB| =45

|HՈB| =50

(|F U H U B|) ̅=50

|F Ո H Ո B| = |F U H U B|-|F|-|H|-|B|+| F Ո H |+| H Ո B |+|F Ո B| =20

Hence, 20 viewers watch all 3 kinds of games.


|F – H- B|=|F| - | F Ո H |-| F Ո B |+| F Ո H Ո B |=190

|H – B - F|=95

|B – F - H|=40

Hence, No of viewers who watch exactly one of the sports = 190+95+40 = 325







Hope it helps


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Answered by jyashaswylenka
97

Answer:

Step-by-step explanation:

Let F denote people watch football.

H denotes people watch hockey.

B denotes people watch basketball.

Now,

|F|=285

|H|=195

|B|=115

|FՈH| =70

|FՈB| =45

|HՈB| =50

(|F U H U B|)'=50

|F Ո H Ո B| = |F U H U B|-|F|-|H|-|B|+| F Ո H |+| H Ո B |+|F Ո B| =20

Hence, 20 viewers watch all 3 kinds of games.

|F – H- B|=|F| - | F Ո H |-| F Ո B |+| F Ո H Ո B |=190

|H – B - F|=95

|B – F - H|=40

Hence, No of viewers who watch exactly one of the sports = 190+95+40 = 325

Plz mark this ans as brainliest plz⤵⬇

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