a survey of town of 400 families conducted , the result was , Number of families = 50, 68,182,74,26 and Number of children = 0,1,2,3,4 . Find the probability that a family has a) 3 Children , b) 2Children
Answers
The probability of having 3 children is 37/ 200 and the probability of having 4 children is 91 / 200.
Step-by-step explanation:
Total number of families = 400
Total number of possible outcomes = 400
(a). Number of families having 3 children = 74
Number of favourable outcomes = 74
Required probability = Number of favourable outcomes / Total number of possible outcomes = 74 / 400 = 37/ 200
(b). Number of families having 2 children = 182
Number of favourable outcomes =182
Required probability = Number of favourable outcomes / Total number of possible outcomes = 182 / 400 = 91 / 200
Thus the probability of having 3 children is 37/ 200 and the probability of having 4 children is 91 / 200.
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The probability of having 3 children is 37/ 200 and the probability of having 4 children is 91 / 200.
Step-by-step explanation:
Total number of families = 400
Total number of possible outcomes = 400
(a). Number of families having 3 children = 74
Number of favorable outcomes = 74
Required probability = Number of favourable outcomes / Total number of possible outcomes = 74 / 400 = 37/ 200
(b). Number of families having 2 children = 182
Number of favorable outcomes =182
Required probability = Number of favourable outcomes / Total number of possible outcomes = 182 / 400 = 91 / 200
Thus the probability of having 3 children is 37/ 200 and the probability of having 4 children is 91 / 200.