A survey shows that 63% of the people in a city read newspaper A whereas 76% read newspaper B.If x% of the people read both the newspapers, then a possible value of x can be D) 55 C) 29 B) 37 A) 65 61
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Given n(A)=63% and n(B)=76%
⇒n(A∪B)=n(A)+n(B)−n(A⋂B)
⇒n(A∪B)=63+76−n(A⋂B)
Since n(A∪B)≤100
⇒63+76−n(A⋂B)≤100
⇒n(A⋂B)≥39
⇒x≥39
Generally n(A⋂B)≤n(A) and n(A⋂B)≤n(B)
⇒n(A⋂B)≤63 and n(A⋂B)≤76
Combining we get ;
⇒n(A⋂B)≤63
⇒x≤63
⇒39≤x≤63
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