Question

A suspended simple pendulum of length l is making an angle theta with the vertical.On releasing its velocity at lowest point will be

Answer 1

Answer:

v=√2gL(1−cosθ)

Explanation:

OC=OBcosθ=Lcosθ

h=OC−OB

h=L(1−cosθ)

KE at C=PE at B

⇒1/2mv2=mgh

⇒v2=2gh

⇒v2=2gL(1−cosθ)

⇒v=√2gL(1−cosθ)

Answer 2

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