a sweet seller has 420 kaju and 130 badam burfis.he wants to stack them in such a way that each stack has the same number and they take up least area of the tray.what is the number of burfis that can be placed in each stack for this purpose?
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Answered by
433
Hi Dear !
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If He want to stack them in such a way that each stack has the same no. and they take up least area of the tray
Then He should find HCF of 420 and 130
420 = 2 x 2 x 5 X 3 X 7
130= 2 x 5 x 13
HCF = 10
So he have 10 stacks
and no. of kaju in 1 stack = 420/10 = 42
no. of badam in 1 stack = 130/10 = 13
_________________________________________________________
If He want to stack them in such a way that each stack has the same no. and they take up least area of the tray
Then He should find HCF of 420 and 130
420 = 2 x 2 x 5 X 3 X 7
130= 2 x 5 x 13
HCF = 10
So he have 10 stacks
and no. of kaju in 1 stack = 420/10 = 42
no. of badam in 1 stack = 130/10 = 13
Answered by
436
HI Friend !!
To Arrange the sweets in such a way that each stack has the same number and they take up least area of the tray , We have to find the H.C.F of 420 and 130.
420 = 130 x 3 + 30
130 = 30 x 4 + 10
30 = 10 x 3 + 0
Hence , H.C.F. = 10
Therefore ,the sweet seller can make 10 stacks each for both the types of sweet.
No: of kaju barfis in 1 stack = 420 / 10 = 42 barfis
NO: of badam barfis in 1 stack = 130 / 10 = 13 barfis
To Arrange the sweets in such a way that each stack has the same number and they take up least area of the tray , We have to find the H.C.F of 420 and 130.
420 = 130 x 3 + 30
130 = 30 x 4 + 10
30 = 10 x 3 + 0
Hence , H.C.F. = 10
Therefore ,the sweet seller can make 10 stacks each for both the types of sweet.
No: of kaju barfis in 1 stack = 420 / 10 = 42 barfis
NO: of badam barfis in 1 stack = 130 / 10 = 13 barfis
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