Question

A sweet seller has 420
kaju burfis and 130 badam burfis he
wants to stack them in such a way
that each stack has the same number
of burfis and they take up the least
area of the tray. What is the number
of burfis that can be placed in each
stack for this purpose? ​

Answer 1

Answer: The area of the tray that is used up in stacking the burfis will be least if the sweet seller stacks the maximum number of burfis in each stack. Since each stack must have the same number of burfis. Therefore, the number of stacks will be least if the number of burfis in each stack is equal to the

HCF of 420 and 130.

In order to find the HCF of 420 and 130, let us apply Euclid's division lemma to 420 and 130 to get

420=130×3+30

Let us now consider the divisor 130 and the remainder 30 and apply division lemma to get

130=30×4+10  

Consider now divisor 30 and the remainder 10 and apply division lemma, we get

30=3×10+0

Since the remainder at this stage is zero. Therefore, the last divisor 10 is the HCF of 420 and 130.

Hence, the sweet seller can make stacks of 10 burfis of each kind to cover the least area of the tray.

Step-by-step explanation: