Question

A sweet seller has 650 Kahului barfing and 1170 balsam barfi she want to stack them in a such way that each stack has the same number of they take up the least area of the tray what is the the number that can be placed in each stack for this purpose

Answer 1

 HCF of 420 and 130.

 HCF of 420 and 130.In order to find the HCF of 420 and 130, let us apply Euclids division lemma to 420 and 130 to get

 HCF of 420 and 130.In order to find the HCF of 420 and 130, let us apply Euclids division lemma to 420 and 130 to get420=130×3+30

 HCF of 420 and 130.In order to find the HCF of 420 and 130, let us apply Euclids division lemma to 420 and 130 to get420=130×3+30Let us now consider the divisor 130 and the remainder 30 and apply division lemma to get

 HCF of 420 and 130.In order to find the HCF of 420 and 130, let us apply Euclids division lemma to 420 and 130 to get420=130×3+30Let us now consider the divisor 130 and the remainder 30 and apply division lemma to get130=30×4+10 

 HCF of 420 and 130.In order to find the HCF of 420 and 130, let us apply Euclids division lemma to 420 and 130 to get420=130×3+30Let us now consider the divisor 130 and the remainder 30 and apply division lemma to get130=30×4+10 Consider now divisor 30 and the remainder 10 and apply division lemma, we get

 HCF of 420 and 130.In order to find the HCF of 420 and 130, let us apply Euclids division lemma to 420 and 130 to get420=130×3+30Let us now consider the divisor 130 and the remainder 30 and apply division lemma to get130=30×4+10 Consider now divisor 30 and the remainder 10 and apply division lemma, we get30=3×10+0

 HCF of 420 and 130.In order to find the HCF of 420 and 130, let us apply Euclids division lemma to 420 and 130 to get420=130×3+30Let us now consider the divisor 130 and the remainder 30 and apply division lemma to get130=30×4+10 Consider now divisor 30 and the remainder 10 and apply division lemma, we get30=3×10+0Since the remainder at this stage is zero. Therefore, last divisor 10 is the HCF of 420 and 130.

 HCF of 420 and 130.In order to find the HCF of 420 and 130, let us apply Euclids division lemma to 420 and 130 to get420=130×3+30Let us now consider the divisor 130 and the remainder 30 and apply division lemma to get130=30×4+10 Consider now divisor 30 and the remainder 10 and apply division lemma, we get30=3×10+0Since the remainder at this stage is zero. Therefore, last divisor 10 is the HCF of 420 and 130.Hence , the sweet seller can make stacks of 10 burfis of each kind to cover the least area of the tray. 

hope it helps you out