A Sweets stall placed an order to Mr. Aditya for making cardboard boxes for packing their
sweets. Two sizes of boxes are ordered. The bigger of dimensions 25cm × 20cm × 5cm and the
smaller of dimensions 15cm × 12cm × 5cm. For all the overlaps, 5% of the total surface is
required extra. 250 boxes of each kind are required. Cost of the cardboard is Rs. 4 for 1000 cm2
.
By mistake Sweets Stall made payment according to the bigger boxes, but Mr. Aditya returned
back the excess money.
(a) What amount was returned back by Mr. Aditya to the Sweets Stall?
(b) Which mathematical concept is used in the above problem?
Answers
Answer:
Dimensions of bigger box = 25cm x 20cm x 5cm
Dimensions of smaller box = 15cm x 12cm x 5cm
To find the total area of cardboard needed for each box we will find the TSA of each box--
TSA of bigger box = 2 (lb + bh + hl) cm²
= 2 (500 + 100 + 125) cm²
= 1450 cm²
It is given that 5% is taken extra for all overlaps,
5% of 1450 cm² = 72.5 cm²
Total area of bigger box = (1450 + 72.5) cm²
= 1522.5 cm²
TSA of smaller box = 2(lb + bh + hl) cm²
= 2(180 + 60 + 75) cm²
= 2 (315) cm²
= 630 cm²
Total area of smaller box = (630 + 31.5) cm²
= 661.5 cm²
Total cost to paid = Rs. 250 (1522.5 + 661.5)
= Rs. 250 x 2184
= Rs. 5,46,000
Amount paid accidentally = Rs. (500 x 1522.5)
= Rs. 7,61,250
(a)
Amount Mr. Aditya returned = Rs. (7,61,250 - 5,46,000)
= Rs. 2,15,250
(b)
The concept of TSA of solids and Few arithmetic concepts are used.
Thank you.....