Physics, asked by shokumari81, 13 days ago

a swimmer can swim at a speed of 0.6m/s with respect to water . she wants to cross a river which is 50 m wide and has a water current of 0.36 m/s . if she wants to reach on the other bank of the point directly opposite to her starting point in which direction she must swim​

Answers

Answered by ayushnishad16p6m8n9
17

Answer:

here is your answer hope it helps

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Answered by steffiaspinno
1

The swimmer should travel in the direction opposite to the flow of river at an angle of 53° with respect to the horizontal.

Given:

Speed of swimmer V_{s}=0.6 m/s

Width of the river =50m

Speed of the water in river V_{w} =0.36m/s

To find:

The direction in which he swimmer should swim in order to reach the exact opposite point.

Solution:

From the figure, lets assume that the swimmer starts swimming from O with a speed V_{s}=0.6m/s. According to the question, the swimmer wants to reach the point P but, as we know, the river is flowing with a velocity V_{w}=0.36m/s.

If the swimmer swims in the direction OP, he will lose the trajectory of the path and miss the point P by flowing in the direction of the river.

To cover this gap, the swimmer needs to swim in the direction opposite to the flow of the river at an angle θ with the horizontal.

Lets assume, the target point of the swimmer be the point O' which makes an angle θ with the river. Hence, with the presence of the flow of river, swimmer reaches the required point P.

Now,

In ΔOAO', we have, ∠AOO'= θ, Hence,

cosθ  =\frac{OA}{O'O}

cosθ  =\frac{0.36}{0.6}

cosθ  =0.6

Hence,

θ =cos^{-1}(0.6)

θ =53^{o}

The swimmer needs to travel with an angle of 53^{o} with respect to the origin with the horizontal.

Final answer:

Hence, the swimmer should travel in the direction opposite to the flow of river at an angle of 53° with respect to the horizontal.

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