A swimmer crosses a flowing stream of width d to and fro in time T1 . The time taken to cover the same distance up and down the stream is T2 then the time the swimmer would take to swim a distance 2d still water is
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Answer:
t^2,1 = t3 + t3
Explanation:
Let v be the river velocity and u the velocity of swimmer in still water. Then
t1=2(Wu2−v2−−−−−−√)
t2=Wu+v+Wu−v=2uWu2−v2andt3=2Wu
Now we can see that t21=t2t3
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