Question

A swimmer crosses a river with minimum possible time 10 second. And when he reaches the other end starts swimming in the direction towards the point from where he started swimming. Keeping the direction fixed the swimmer crosses the river in 15 sec. The ratio of speed of swimmer with respect to water and the speed of river flow is?

Answer 1

Answer:

For given situation

10= d/ Vp sin(θ)

For min. time θ=90

Thus sin θ=1

Now  

Vp= d/10

Drift= Vw(10)

Now for second situation

15= d/Vp cosθ

So

Cos θ= 10/15=2/3

Now he has to get back to initial point

Vw(10)^2=  (Vp sin θ – Vw ) 153

25 Vw= 1 5Vw = 3Vp sinθ

Now

Vp/Vw =3/5 √1.4/9

Explanation:

Answer 2

Answer:

solution to the question is provided above