Question

A swimmer jumps in to a swimming tank and was swimming at 8m below the surface of the tank. Calculate the pressure on him . (Density of water -1000 kg/m³, g=9.8 m/s², atmospheric pressure= 1.013×10^5N/m²) *
2 points
1×10^7 N/m²
2×10^-8 N/m²
1.797×10^5N/m²
1.797×10^-5 N/m​

Answer 1

Explanation:

I hope you have understood the question

Answer 2

The Pressure on the swimmer is 1.797 × 10⁵N/m². So, option 'C' is correct.

Given:-

Height below the swimming surface = 8m

The density of water = -1000kg/m³

g = 9.8m/s²s²

Atmospheric pressure = 1.013 × 10⁵N/m²

To Find:-

The Pressure on the swimmer.

Solution:-

We can easily calculate the Pressure on the swimmer by using these simple steps.

As

Height below the swimming surface (h) = 8m

The density of water (d) = -1000kg/m³

g = 9.8m/s²s²

Atmospheric pressure (Po) = 1.013 × 10⁵N/m²

Pressure on the swimmer (P) =?

Gauge pressure = d×g×h

According to the Formula,

Pressure on swimmer = Atmospheric pressure + Gauge Pressure

$P = Po + dgh$

On putting the values, we get

$P = 1.013 \times {10}^{5} + (1000 \times 9.8 \times 8)$

$P = 1.013 \times {10}^{5} + (1000 \times 78.4)$

$P = 1.013 \times {10}^{5} + 0.784 \times {10}^{5}$

$P = 1.797 \times {10}^{5}$

Hence, The Pressure on the swimmer is 1.797 × 10⁵N/m². So, option 'C' is correct.

#SPJ2