A swimmer moves through the water at a speed of 0.45 m/s. The drag force opposing this motion is 124 N. How much
power is developed by the swimmer?
Select one:
A. 55.8 W
B. 275.0W
C. 874 W
D. 457 W
Answers
Answered by
2
Answer:
to obtain power developed by the swimmer (p), substitute 124 Newton for F and 0.45 m/s for v in the equation p=Fv
p=(124N)(0.45m/s)
p=(55.8 N.m/s)(1w/1N.m/s)
p=55.8W
therefore power developed by the swimmer is 55.8 W
Answered by
0
Answer:
B
Explanation:
Power = f x v
124 x 0.45 = 275 whatt
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