A swimmer overcame a raft of wooden block at a point B, when he was in downstream motion. 50 minute
later be turned back and after some time passed the wooden block at a distance 3km from the point B. Find
the stream velocity assuming the swimming speed is constant.
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Explanation:
Considering the given figure below.
Let v
0
be the stream velocity and v
′
the velocity of motorboat with respect to water. The motorboat reached point B while going downstream with velocity (v
0
+v
′
) and then returned with velocity (v
′
−v
0
) and passed the raft at point C. Let t be the time for the raft (which flows with stream with velocity v
0
) to move from point A to C, during which the motorboat moves from A to B and then from B to C.
Therefore
v
0
l
=τ+
(v
′
−v
0
)
(v
0
+v
′
)τ−l
On solving, we get v
0
=
2τ
l
=3km/hr.
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