A swimmer overcame a raft of wooden block at a point b, when he was in downstream motion.50 minutes later be turned back and after some time passed the wooden block at a distance 3km from the point . Find the stream velocity assuming the swimming speed is constant.
(Please write the answer including all steps and procedures and please don't write irrelevant answers. Answer the question if you know it or else no need.)
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Considering the given figure below.
Let v0 be the stream velocity and v′ the velocity of motorboat with respect to water. The motorboat reached point B while going downstream with velocity (v0+v′) and then returned with velocity (v′−v0) and passed the raft at point C. Let t be the time for the raft (which flows with stream with velocity v0) to move from point A to C, during which the motorboat moves from A to B and then from B to C.
Therefore
v0l=τ+(v′−v0)(v0+v′)τ−l
On solving, we get v0=2τl=3km/hr.
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