a swimmer swim in a 90 m long pool . he covers a distance of 180 m by swimming from 1 side end to the another back along the same path .if he cover the first 90 m at a speed of 2 m second ,then how fast should he swim so that his average speed is 3 m second
Answers
Answered by
7
hy
friend
here is your answer°°°°
→ The pool Length is = 90m
→ Speed to cover first 90 m = 2 m/s
Speed = distance / time
Time = distance / speed
Time taken to cover first 90 m
= 90 / 2
= 45 sec
Time taken to travel the next 90 m back = t₂
→Total distance
= 180 m
Therefore
Total time to cover
180 m = 45 + t₂
Average speed to travel
180 m = 3 m/s
or
Average speed
= Total distance covered / Total time taken
3 m/s = 180 / 45 + t₂
By cross multiplication
we get the following result 3 x (45 +t₂) = 180 or t2= 15
hence
time taken to travel back 90 m = 15 sec
To cover his average speed is 3m/s ?
Speed = distance / time
∴ he must swim with a speed of 6 sec to make
∴ his average speed to be 3 m/s
Swayze:
thakyou........swati
Similar questions