A swimmer swims 90m long pool. He covers the distance of 180m by swimming from
one end to other end back along the same path. If he covers the first 90m at speed of 2m/s,
then how fast he swim so that his average speed is 3m/s
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Answer:
Total Pool distance=90m
Total Distance=180m
Speed in first round 90m =2m/s
Let speed in second one=x
Average speed=3m/s
t1=distance/speed , i.e 90/2=45 seconds
t2=90/x
now equate the whole equation
Average speed = Total Distance /Total Time taken
=3=180/45+90/x
=3= 180x/45+90=3=180x/135
=3×135=180x
405=180x
405/180=x
2.25
Explanation:
You can use it perfectly ...I have explained it in the solution
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