A swimmer who can swim with speed 10 m/s in still water crosses the river of width 100 m in minimum possible time. Time of crossing the river is equal to ____ S.
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2
10 S
time = length / speed
= 100 /10 s
= 10 s
Answered by
1
Answer:
given,
u=10m/s
v=0
s=100m
V^2-U^2=2as. (3rd law of motion)
0-100=2×a×100
-100=200a
therefore a=-2
using 1st law of motion we would find t
V=U+AT
0=10+2t
-10=2t
t=5s
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