Question

A swimming bath is 300m long, 30m wide. It is 1m deep at the shallow end and 4m deep at the other end. Find the volume of water when it is full​

Answer 1

The cross section of the swimming pool is a trapezium with parallel sides 1.5m and 3m (depth of both ends) and 40m (length of pool) as the ⊥ r distance between ∥ sides.

The cross section of the swimming pool is a trapezium with parallel sides 1.5m and 3m (depth of both ends) and 40m (length of pool) as the ⊥ r distance between ∥ sides.The width of pool 1.5m can be the length of  cross section.

The cross section of the swimming pool is a trapezium with parallel sides 1.5m and 3m (depth of both ends) and 40m (length of pool) as the ⊥ r distance between ∥ sides.The width of pool 1.5m can be the length of  cross section.Length of swimming pool=40m

The cross section of the swimming pool is a trapezium with parallel sides 1.5m and 3m (depth of both ends) and 40m (length of pool) as the ⊥ r distance between ∥ sides.The width of pool 1.5m can be the length of  cross section.Length of swimming pool=40mBreadth of the pool=15m

The cross section of the swimming pool is a trapezium with parallel sides 1.5m and 3m (depth of both ends) and 40m (length of pool) as the ⊥ r distance between ∥ sides.The width of pool 1.5m can be the length of  cross section.Length of swimming pool=40mBreadth of the pool=15mDepth of the pool=1.5m and 3m

The cross section of the swimming pool is a trapezium with parallel sides 1.5m and 3m (depth of both ends) and 40m (length of pool) as the ⊥ r distance between ∥ sides.The width of pool 1.5m can be the length of  cross section.Length of swimming pool=40mBreadth of the pool=15mDepth of the pool=1.5m and 3m∴ Volume of the water=21[(1.5+3)×40]×15m3

The cross section of the swimming pool is a trapezium with parallel sides 1.5m and 3m (depth of both ends) and 40m (length of pool) as the ⊥ r distance between ∥ sides.The width of pool 1.5m can be the length of  cross section.Length of swimming pool=40mBreadth of the pool=15mDepth of the pool=1.5m and 3m∴ Volume of the water=21[(1.5+3)×40]×15m3                                  =21×4.5×40×15m3

The cross section of the swimming pool is a trapezium with parallel sides 1.5m and 3m (depth of both ends) and 40m (length of pool) as the ⊥ r distance between ∥ sides.The width of pool 1.5m can be the length of  cross section.Length of swimming pool=40mBreadth of the pool=15mDepth of the pool=1.5m and 3m∴ Volume of the water=21[(1.5+3)×40]×15m3                                  =21×4.5×40×15m3                                  =1350m3

The cross section of the swimming pool is a trapezium with parallel sides 1.5m and 3m (depth of both ends) and 40m (length of pool) as the ⊥ r distance between ∥ sides.The width of pool 1.5m can be the length of  cross section.Length of swimming pool=40mBreadth of the pool=15mDepth of the pool=1.5m and 3m∴ Volume of the water=21[(1.5+3)×40]×15m3                                  =21×4.5×40×15m3                                  =1350m3Capacity of water in litres =1350×1000litres   (1m3=1000litres)

The cross section of the swimming pool is a trapezium with parallel sides 1.5m and 3m (depth of both ends) and 40m (length of pool) as the ⊥ r distance between ∥ sides.The width of pool 1.5m can be the length of  cross section.Length of swimming pool=40mBreadth of the pool=15mDepth of the pool=1.5m and 3m∴ Volume of the water=21[(1.5+3)×40]×15m3                                  =21×4.5×40×15m3                                  =1350m3Capacity of water in litres =1350×1000litres   (1m3=1000litres)                                           =1350000litres

im not sure that answer ia correct

Answer 2

You have to make a diagram to better understand this

Volume = area of cross section X Length