A swimming pool 20 m in length , 15 m in breadth , 4 m in depth. Find the cost of cementing its floor and walls at ₹ 35 per m square.
Answers
the length of swimming pool = 20m
the breadth of swimming pool = 15m
the depth of swimming pool = 4m
lateral surface area = 2lh+2lw+2hw
= 2(20×15)+2(20×15)+2(15×15)
= 600+600+450 = 1650
the cost of cementing the floor = 825×35 = 28,875
HEY BUDDY..!!
HERE'S THE ANSWER..
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♠️ It is logical question with mensuration ,
▶️ It is clear that we have to cement only 5 sides , 4 lateral sides and from bottom.. Using this concept our formula become
✔️ Area to be cemented = Total surface area - area of top .
=> Area to be cemented = 2 [ ( L × B ) + ( B × H ) + ( H × L ) ] - [ L × B ]
⏺️L ( length ) = 20 m
⏺️B ( breadth ) = 15 m
⏺️H ( depth or height ) = 4 m
⏺️ Now putting values in formula...
=> Area to be cemented = 2 [ ( 20 × 15 ) + ( 15 × 4 ) + ( 4 × 20 ) ] - [ 20 × 15 ]
=> Area to be cemented = 2 [ ( 300 ) + ( 60 ) + ( 80 ) ] - [ 300 ]
=> Area to be cemented = 2 [ 440 ] - [ 300 ]
=> Area to be cemented = 880 - 300
=> [ Area to be cemented = 580 m^2 ]✔️
▶️ Now cost of cementing is ₹ 35 per metre square , So cost of cementing 560 m^2
=> Cost = 580 × 35
=> [ Cost = ₹ 20,300 ] ✔️✔️
▶️ Cost of cementing will be ₹ 20,300
HOPE HELPED ..
JAI HIND..
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