Question

A swimming pool 70m×44m×3m is filled by water issuing from a pipe of diameter 35cm at 6m per second. How many hours does it take to fill the pool ???​

Answer 1

Given :-

◉ Dimensions of Swimming pool:

• Length, l = 70 m
• Breadth, b = 44 m
• Height, h = 3 m

◉ Dimensions of Pipe:

• Diameter, d = 35 cm or 0.35 m
• Length, l = 6 m [∵ The water flows at the rate of 6 m per second, So In 1 second It would cover 6 m or the length of the pipe]

To Find :-

◉ Time taken to fill the swimming pool.

Solution :-

We know,

Time taken will be equal to the volume of swimming pool divided by the volume of water flown in one second.

Since, The swimming pool is in the shape of a cuboid.

∴ Volume of Swimming Pool = L × B × H

⇒ V = 70 × 44 × 3

⇒ V = 9240 m³

Now, Because the pipe is in the shape of a cylinder

∴ Volume of Water flown in one second = πr²h

⇒ v = 22/7 × (0.35/2) × (0.35/2) × 6

⇒ v = 11 × 3 × 0.05 × 0.35

⇒ v = 0.57, ≈ 0.6 m³

Now,

Time taken(in seconds) = V / v

⇒ t = 9240 / 0.6

⇒ t = 15400 s, or 4.27 hours

More Information :-

⇒ Volume of Cube = (side)³

⇒ Volume of Sphere = (4πr³)/3

Where,

• r = radius of sphere

Answer 2

Answer:

Answer:

83.3 hours

Step-by-step explanation:

Dimensions of swimming pool are: length =70 m

breadth = 44 m

depth(height) =3 m

Volume of pool = l × b ×h

= 70 m× 44 m× 3 m

Also,

diameter of pipe = 14 cm

radius of pipe = 7 cm

Let the height (depth) be 2 m

Then,volume of water flowed in 1 second = πr^2h

=22 × 0.07 m × 0. 07m × 2 m

7

Volume of water flowed in 1 hour = πr^2h ×3600

(1hour =3600 seconds)

=22 × 0.07 m ×0.07 m × 2 × 3600

7

Total time taken to fill the pool = (volume of pool) / (volume of pipe)

=(70 × 44 × 3) / 3.14× 0.07 × 0.07 × 2 × 3600

=83.3 hours.

Hope it helps.