A swimming pool 70m long, 44m wide, 3 m deep is filled by water issuing from a pipe of diameter 14 cm , at 2 m per second. How many hours does it take to fill the bath?
Answers
Answer:
83.3 hours
Step-by-step explanation:
Dimensions of swimming pool are: length =70 m
breadth = 44 m
depth(height) =3 m
Volume of pool = l × b ×h
= 70 m× 44 m× 3 m
Also,
diameter of pipe = 14 cm
radius of pipe = 7 cm
Let the height (depth) be 2 m
Then,volume of water flowed in 1 second = πr^2h
=22 × 0.07 m × 0. 07m × 2 m
7
Volume of water flowed in 1 hour = πr^2h ×3600
(1hour =3600 seconds)
=22 × 0.07 m ×0.07 m × 2 × 3600
7
Total time taken to fill the pool = (volume of pool) / (volume of pipe)
=(70 × 44 × 3) / 3.14× 0.07 × 0.07 × 2 × 3600
=83.3 hours.
Hope it helps.
Answer:
Answer:
Hence,the pipe takes in fraction 4 4/9 hrs to fill the swimming pool
Step-by-step explanation:
Given :
Length of a swimming pool(l)= 70 m
Breadth of a swimming pool(b)= 44 m
Height of a swimming pool(h)= 3 m
Diameter of pipe(d)=35 cm=
Radius of pipe(r) = d/2= 35/2= 17.5 cm= 17.5/100= .175 m
Length of water(h) flowing in a pipe in x seconds = 6 x
Capacity of swimming pool= l× b×h
Volume of pipe = πr²h
Volume of water flowing through a cylindrical pipe =Capacity of swimming pool
πr²h= l× b×h
22/7×(.175)²×6 × x =70×44×3
22/7×.175 × .175×6x =70×44×3
x= (70× 44× 3× 7) / ( 22× .175× .175 × 6)
x= 10000000/25×25= 10000000/625
x= 16000 sec
x= 16000/3600 hrs
x= 40/9 hrs= 4 4/9 hrs
Hence,the pipe takes in fraction 4 4/9 hrs to fill the swimming pool