A swimming pool 70m long , 44m wide and 3 m deep, is filled by water issuing from a pipe of a diameter 35cm , at 6 m per second. How many hours does it take to fill the pool?
Answers
Answer:
3.5 hours
Step-by-step explanation:
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Answer:
Given :-
◉ Dimensions of Swimming pool:
- Length, l = 70 m
- Breadth, b = 44 m
- Height, h = 3 m
◉ Dimensions of Pipe:
- Diameter, d = 35 cm or 0.35 m
- Length, l = 6 m [∵ The water flows at the rate of 6 m per second, So In 1 second It would cover 6 m or the length of the pipe]
To Find :-
◉ Time taken to fill the swimming pool.
Solution :-
We know,
Time taken will be equal to the volume of swimming pool divided by the volume of water flown in one second.
Since, The swimming pool is in the shape of a cuboid.
∴ Volume of Swimming Pool = L × B × H
⇒ V = 70 × 44 × 3
⇒ V = 9240 m³
Now, Because the pipe is in the shape of a cylinder
∴ Volume of Water flown in one second = πr²h
⇒ v = 22/7 × (0.35/2) × (0.35/2) × 6
⇒ v = 11 × 3 × 0.05 × 0.35
⇒ v = 0.57, ≈ 0.6 m³
Now,
Time taken(in seconds) = V / v
⇒ t = 9240 / 0.6
⇒ t = 15400 s, or 4.27 hours
More Information :-
⇒ Volume of Cube = (side)³
⇒ Volume of Sphere = (4πr³)/3
Where,
r = radius of sphere